// *Wyznacznik - w/g definicji permutacyjnej*, Krzysztof Bosak 02.11.1998

#include <iostream.h>
#include <string.h>

class det
{
	char *tab, len;
	double *matrix, result;
	bool par;
	void per(int count)
	{
		if(count<len-1)
		{
			per(count+1);
			char temp;
			for(int xcount=count+1; xcount<len; xcount++)
			{	
				temp=tab[count];
				tab[count]=tab[xcount];
				tab[xcount]=temp;
				par=!par;
				per(count+1);
				tab[xcount]=tab[count];
				tab[count]=temp;
				par=!par;
			}			
		}
		else
		{
			double mul=matrix[len**tab];
			//cout<<"a[0,"<<long(tab[0])<<"]*";*/
			for(int z=1; z<len; z++)
			{
				//cout<<"a["<< z <<","<<long(tab[z])<<"]*";
				mul*=matrix[z+len*tab[z]];
			}
			if(par)
				result+=mul;
			else
				result-=mul;
/*			cout<<"="<<mul<<"   "<<"\t"<<long(par)<<"\t";
			for(int i=0; i<len; i++)
				cout<<long(tab[i]);
			if(par)
				cout<<" P\n";
			else
				cout<<endl;*/
		}
	}
public:
	det(char l, double *mat): len(l), matrix(mat), result(0), par(true)
	{
		tab=new char[len];
		for(char i=0; i<len; i++)
			tab[i]=i;
		per(0);
		cout<<result;
	}
	~det()
	{
		delete []tab;
	}
};

main()
{
	double mat[]={1, 2, 3, 4, 5, 6, 7, 8, 9,  10, 11, 132, 1133, 114, 115, 119};//4x4 ==> 489600
	det p(2, mat);
	return 0;
}